[AgainstAllOdds]

These have nothing to do with GAMBLING...but im dead if I dont get these down and I cant figure the fuks out to save my life...any help would be great.

1. Solve the Radical equation...

Square root of x+2 = 1+ square root of x-5

2. Simplfy the expression without leaving any roots on the bottom.

5
____
(square root of 13) -3

* you have to multiply top and bottom by the conjugate of (square root of 13)-3

I would make them look nice like ganch but I dont know how. Thanks to anyone that can help me out.

[BuddyBear]

One thing I always learned in my stats courses was that about half the answers are either "1" or "0"

[Ganchrow]

Originally Posted by AgainstAllOdds

These have nothing to do with GAMBLING...but im dead if I dont get these down and I cant figure the fuks out to save my life...any help would be great.

1. Solve the Radical equation...

Square root of x+2 = 1+ square root of x-5

2. Simplfy the expression without leaving any roots on the bottom.

5
____
(square root of 13) -3

* you have to multiply top and bottom by the conjugate of (square root of 13)-3

I would make them look nice like ganch but I dont know how. Thanks to anyone that can help me out.

So how have you tried solving these two problems?

[AgainstAllOdds]

Ganch, thats the point...I cant...I try multiplying this and that and nothing seems to be adding up right....if you could help me out with these I swear I will never ask you for anything ever again...

[Ganchrow]

Originally Posted by AgainstAllOdds

Ganch, thats the point...I cant...I try multiplying this and that and nothing seems to be adding up right

Be more specific about what you've tried.

In the first problem, what happened when you squared each side of the equation?

In the second problem, what happened when you multiplied numerator and denominator by (sqrt(13)+3)?

[AgainstAllOdds]

ganch,

1 problem I get x+2= 2+ 2sqrt of x-5) + ? I cant multiple sqrt times each other.

2. I get 15 sqrt of 13 on top then on bottm I get 169 - 3(sqrt 13)...which puts me back in the same boat as before...

[Ganchrow]

Originally Posted by AgainstAllOdds

1 problem I get x+2= 2+ 2sqrt of x-5) + ? I cant multiple sqrt times each other.

2. I get 15 sqrt of 13 on top then on bottm I get 169 - 3(sqrt 13)...which puts me back in the same boat as before...

You're not correctly cross multiplying.

Remember:

(a+b) * (c+d) = ac + ad + bc + bd

So with:

sqrt(x+2) = 1 + sqrt(x-5)

If you square both sides:

(x+2) = 1 + 2*sqrt(x-5) + (x-5)

You should be able to take it from there.

[AgainstAllOdds]

so subtract x-4 from both sides and you get -2=2*sqrt(x-5) ... is that correct? Then I would have to square both sides again?

Also, what about problem 2? I get 15 sqrt of 13 on top then on bottm I get 169 - 3(sqrt 13)...which puts me back in the same boat as before...

[Ganchrow]

Originally Posted by AgainstAllOdds

so subtract x-4 from both sides and you get -2=2*sqrt(x-5) ... is that correct? Then I would have to square both sides again?

No, if you subtract (x-4) from both sides you get:

(x+2) - (x-4) = 1 + 2*sqrt(x-5) + (x-5) - (x-4)
6 = 2*sqrt(x-5)

Originally Posted by AgainstAllOdds

Also, what about problem 2? I get 15 sqrt of 13 on top then on bottm I get 169 - 3(sqrt 13)...which puts me back in the same boat as before...

No, you're not cross-multiplying correctly. Try doing it again carefully.

Numerator = 5 * (sqrt(13)+3)
Denominator = (sqrt(13)-3) * (sqrt(13)+3)

[AgainstAllOdds]

Originally Posted by Ganchrow

No, if you subtract (x-4) from both sides you get:

(x+2) - (x-4) = 1 + 2*sqrt(x-5) + (x-5) - (x-4)
6 = 2*sqrt(x-5)

So then I will have to square both sides again?

36=1+x-5
32=x ... is this correct?

Originally Posted by Ganchrow

No, you're not cross-multiplying correctly. Try doing it again carefully.

Numerator = 5 * (sqrt(13)+3)
Denominator = (sqrt(13)-3) * (sqrt(13)+3)

Num - 5(sqrt 13) + 15 ...what does this equal?
Den - 13-3 = 10 or 13-9=4 ...which one?

[Ganchrow]

Originally Posted by AgainstAllOdds

So then I will have to square both sides again?

36=1+x-5
32=x ... is this correct?

No.

6 = 2*sqrt(x-5)
6² = (2*sqrt(x-5))²
36 = 4 * (x-5)
9 = x-5
x = 14

Originally Posted by AgainstAllOdds

Num - 5(sqrt 13) + 15 ...what does this equal?

It just equals 5 * (sqrt(13)+3). Remember -- you only need to remove the radical from the denominator, not the numerator.

Originally Posted by AgainstAllOdds

Den - 13-3 = 10 or 13-9=4 ...which one?

I'm not sure how you got 13-3, but it's incorrect.

Denominator = (sqrt(13)-3) * (sqrt(13)+3)
= (sqrt(13) * sqrt(13) + 3*sqrt(13) - 3*sqrt(13) - 9)
= 13 - 9 = 4

So the answer would be:

⁵/₄*(sqrt(13) + 3)

(As an aside, and with all due respect, if you have any desire to continue your education in math or the sciences, or if you ever want to get serious about sports betting, I'd have to suggest taking some time to brush up on your elementary algebra.)

[AgainstAllOdds]

Originally Posted by Ganchrow

No.

6 = 2*sqrt(x-5)
6² = (2*sqrt(x-5))²
36 = 4 * (x-5)
9 = x-5
x = 14

It just equals 5 * (sqrt(13)+3). Remember -- you only need to remove the radical from the denominator, not the numerator.

I'm not sure how you got 13-3, but it's incorrect.

Denominator = (sqrt(13)-3) * (sqrt(13)+3)
= (sqrt(13) * sqrt(13) + 3*sqrt(13) - 3*sqrt(13) - 9)
= 13 - 9 = 4

So the answer would be:

⁵/₄*(sqrt(13) + 3)

(As an aside, and with all due respect, if you have any desire to continue your education in math or the sciences, or if you ever want to get serious about sports betting, I'd have to suggest taking some time to brush up on your elementary algebra.)

Well thank you...

As a side note, I am not bad at Math, just have not dealt with Radicals in a long time. Once I got passed these I wont have to deal with them again. To put it mildly, Radicals have never been my friend anyway.

[durito]

You are too nice Ganch.

[ChuteBoxe]

[flyingillini]

Ganch is the man