[Iwinyourmoney]

So I was just thinking about this in the shower. For this deal, throw the spreads out the window.

1) A NFL weekend after byeweeks, there are 16 games a week. If I wanted to do a 16-team parlay, and have to pick every game (no O/U), ect.). Just one pick per game. How many different cards would I have to fill out to get EVERY SINGLE possible combination, which would give a guarentee win. Obviously I am not going to do it, its way to much to even try. Just wondering.

2). If I wanted to play the Mega Millions Lottery, and wanted every combination to guarentee a win, how many would there be? (If your not fimailar, the lottery has balls 1-75. There is also a "Mega Ball" number 1-75. You need to match 5/5 of the regular lottery balls, the you have to match you mega ball, the mega ball drawing is in a seperate container then the regular lottery, so # repeat is possible).


................Good luck

[etothep]

haha, you testing them?

[pokernut9999]

seems like the mega millions is like 175,711,536 combos

[pico]

Originally Posted by Iwinyourmoney

So I was just thinking about this in the shower. For this deal, throw the spreads out the window.

1) A NFL weekend after byeweeks, there are 16 games a week. If I wanted to do a 16-team parlay, and have to pick every game (no O/U), ect.). Just one pick per game. How many different cards would I have to fill out to get EVERY SINGLE possible combination, which would give a guarentee win. Obviously I am not going to do it, its way to much to even try. Just wondering.

2). If I wanted to play the Mega Millions Lottery, and wanted every combination to guarentee a win, how many would there be? (If your not fimailar, the lottery has balls 1-75. There is also a "Mega Ball" number 1-75. You need to match 5/5 of the regular lottery balls, the you have to match you mega ball, the mega ball drawing is in a seperate container then the regular lottery, so # repeat is possible).


................Good luck

you need 8 for 3 teamer. 16 or 4 teamer, 32 for 5 teamer, 64 for 6 teamer...just multiply 2 for every extra team. you have a claculator

[pico]

Originally Posted by pokernut9999

seems like the mega millions is like 17+ million combos

for mega million 56 pick 5 and 1 in 42 for mega ball, the odds is about 1/178million

[CrazyL]

Just you'll get the same result without the suspense.

[Louisvillekid1]

Ha, Hope your not thinking this is a way to beat the system. . .

[pico]

Originally Posted by Louisvillekid1

Ha, Hope your not thinking this is a way to beat the system. . .

i do 8 bets for 3 teams parlays for my free plays. that is one way to beat the system.

[HedgeHog]

I believe the answer to question one is 65,536 combinations. Each game offers you 2 choices and there are 16 games. So the answer is 2 to the 16th power or 65,536.

[pico]

Originally Posted by HedgeHog

I believe the answer to question one is 65,536 combinations. Each game offers you 2 choices and there are 16 games. So the answer is 2 to the 16th power or 65,536.

i can gurantee you that the parlay odds for 16 games is less than +6,553,600

[pokernut9999]

?????/

[HedgeHog]

To answer question #2, I need to correct your given info. There are actually 56 regular balls, of which 5 are chosen, and 46 mega balls (sounds dirty) of which one is chosen.

The formula is [56!/ (5! x 51!) ] x 46 = 175,711,536 possibilities.

P.S. 5! = 5x4x3x2x1

I confirmed the answer at the MM site. Do the math for yourself...it works.

[pokernut9999]

Originally Posted by HedgeHog

To answer question #2, I need to correct your given info. There are actually 56 regular balls, of which 5 are chosen, and 46 mega balls (sounds dirty) of which one is chosen.

The formula is [56!/ (5! x 51!) ] x 46 = 175,711,536 possibilities.

P.S. 5! = 5x4x3x2x1

I confirmed the answer at the MM site. Do the math for yourself...it works.

wow , same answer i posted an hour ago.

[HedgeHog]

Originally Posted by pokernut9999

wow , same answer i posted an hour ago.

I know. I just wanted to show the math behind your answer. Then I went to the Mega Millions site to confirm your devine genius

[pokernut9999]

Originally Posted by HedgeHog

I know. I just wanted to show the math behind your answer. Then I went to the Mega Millions to confirm your devine genius

[Ganchrow]

Originally Posted by Iwinyourmoney

1) A NFL weekend after byeweeks, there are 16 games a week. If I wanted to do a 16-team parlay, and have to pick every game (no O/U), ect.). Just one pick per game. How many different cards would I have to fill out to get EVERY SINGLE possible combination, which would give a guarentee win. Obviously I am not going to do it, its way to much to even try. Just wondering.

Just as Hedgehog and Picoman explained, you would need 2¹⁶ = 65,536 different cards to cover all possible outcomes.

Were you to receive true parlay odds, each parlay would pay out at US odds of about +3,113,234.

By betting $1 on each of the 65,536 parlays (and assuming no pushes) you would lock in a loss of $65,535 - $31,132.34 = $34,402.66 (or $34,402.66 / $65,535 ≈ 52.49% of the initial investment).

Originally Posted by Iwinyourmoney

2). If I wanted to play the Mega Millions Lottery, and wanted every combination to guarentee a win, how many would there be? (If your not fimailar, the lottery has balls 1-75. There is also a "Mega Ball" number 1-75. You need to match 5/5 of the regular lottery balls, the you have to match you mega ball, the mega ball drawing is in a seperate container then the regular lottery, so # repeat is possible).

Based on the game as you've descibed it (which is a bit different from the actual Mega Millions^WK), the probability of hitting the first 5 balls would be 1/combin(75,5) = 1/17,259,390 (where combin() refers to the Excel combinatorial function).

The probability of hitting the first 5 balls and the Mega Ball would then be 1/17,259,390/75 = 1 / 1,294,454,250 ≈ 0.00000007725%.

So to answer your actual question, if you wanted to guarantee a win you'd need to buy 1,294,454,250 tickets.