So Bankroll if $10k:
NBA Total for this game is, UNDER 200 +100,
OVER 200 1/2 +110.
Odds to tie at 200 for this game is 2% ( which represent losing one side out right.)
How much should I wager?
Both side has +EV.
Thanks in advance.
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It is a Kelly problem. If you "dutch" it - 100 to win 100, 95 to win (roughly 105), you either
win 5 (98%)
or lose 95.
EP = 0.98 (5) - 0.02 (95) = 4.9 - 1.9 = 3
$3 profit with $195 capital: EV = 1.54
Odds of you winning are 98:2, or 49:1.
Your optimal risk amount would then be (49) (1.54) = 75.46% of your capital (split between the two sides). I'm doing this quickly, so pardon any mistakes... but this split would more than double your bankroll ever 50 opportunities.
Even a modest bankroll will max out the limits on the offering. Once your hedging does this, I'd figure out which side is the right side, and max that (hedging the other side to taste).
I'm not sure the formula works quite right here. That is to determine the amount at risk. In this example, roughly half your stake is at risk of loss.
another way to solve this:
assume you risk x percent of your bankroll. Assume you win 49 times, lose 1 time. What x gives you the highest return?
I agree with Dunder's warning though - I think 2.0 is conservative for the push on an NBA total. 2.2% would be my best guess.
anyone like beer
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