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12-06-2007, 01:59 PM
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#1 (permalink)
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SBR MVP
Join Date: 04-18-07
Posts: 2,640
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Gambling MATH people, question for ya (GANCH)
So I was just thinking about this in the shower. For this deal, throw the spreads out the window.
1) A NFL weekend after byeweeks, there are 16 games a week. If I wanted to do a 16-team parlay, and have to pick every game (no O/U), ect.). Just one pick per game. How many different cards would I have to fill out to get EVERY SINGLE possible combination, which would give a guarentee win. Obviously I am not going to do it, its way to much to even try. Just wondering.
2). If I wanted to play the Mega Millions Lottery, and wanted every combination to guarentee a win, how many would there be? (If your not fimailar, the lottery has balls 1-75. There is also a "Mega Ball" number 1-75. You need to match 5/5 of the regular lottery balls, the you have to match you mega ball, the mega ball drawing is in a seperate container then the regular lottery, so # repeat is possible).
................Good luck
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12-06-2007, 02:04 PM
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#2 (permalink)
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SBR High Roller
Join Date: 09-14-07
Posts: 215
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haha, you testing them?
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12-06-2007, 02:05 PM
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#3 (permalink)
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SBR Hall of Famer
Join Date: 07-25-07
Location: South Carolina
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seems like the mega millions is like 175,711,536 combos
Last edited by pokernut9999 : 12-06-2007 at 02:08 PM.
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12-06-2007, 02:06 PM
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#4 (permalink)
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SBR Hall of Famer
Join Date: 04-05-07
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Quote:
Originally Posted by Iwinyourmoney
So I was just thinking about this in the shower. For this deal, throw the spreads out the window.
1) A NFL weekend after byeweeks, there are 16 games a week. If I wanted to do a 16-team parlay, and have to pick every game (no O/U), ect.). Just one pick per game. How many different cards would I have to fill out to get EVERY SINGLE possible combination, which would give a guarentee win. Obviously I am not going to do it, its way to much to even try. Just wondering.
2). If I wanted to play the Mega Millions Lottery, and wanted every combination to guarentee a win, how many would there be? (If your not fimailar, the lottery has balls 1-75. There is also a "Mega Ball" number 1-75. You need to match 5/5 of the regular lottery balls, the you have to match you mega ball, the mega ball drawing is in a seperate container then the regular lottery, so # repeat is possible).
................Good luck
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you need 8 for 3 teamer. 16 or 4 teamer, 32 for 5 teamer, 64 for 6 teamer...just multiply 2 for every extra team. you have a claculator
__________________
"But you can't have your dream without laying something on the line. The key is not to risk what you can't afford to lose. You might think you're different, but someday you gonna want more too. The quesiton is what are you willing to lay on the line."
钱 錢 argent Geld soldi お金 돈 dinheiro деньги dinero เงิน כסף, ממון raha λεφτά pengar danh từ money
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12-06-2007, 02:06 PM
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#5 (permalink)
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SBR Hall of Famer
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Quote:
Originally Posted by pokernut9999
seems like the mega millions is like 17+ million combos
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for mega million 56 pick 5 and 1 in 42 for mega ball, the odds is about 1/178million
__________________
"But you can't have your dream without laying something on the line. The key is not to risk what you can't afford to lose. You might think you're different, but someday you gonna want more too. The quesiton is what are you willing to lay on the line."
钱 錢 argent Geld soldi お金 돈 dinheiro деньги dinero เงิน כסף, ממון raha λεφτά pengar danh từ money
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12-06-2007, 02:07 PM
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#6 (permalink)
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VIP Moderator
Join Date: 08-02-07
Posts: 15,950
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Just  you'll get the same result without the suspense.
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12-06-2007, 02:10 PM
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#7 (permalink)
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SBR MVP
Join Date: 10-17-07
Location: Atlantic City
Posts: 4,179
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Ha, Hope your not thinking this is a way to beat the system. . .
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12-06-2007, 02:13 PM
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#8 (permalink)
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SBR Hall of Famer
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Quote:
Originally Posted by Louisvillekid1
Ha, Hope your not thinking this is a way to beat the system. . .
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i do 8 bets for 3 teams parlays for my free plays. that is one way to beat the system.
__________________
"But you can't have your dream without laying something on the line. The key is not to risk what you can't afford to lose. You might think you're different, but someday you gonna want more too. The quesiton is what are you willing to lay on the line."
钱 錢 argent Geld soldi お金 돈 dinheiro деньги dinero เงิน כסף, ממון raha λεφτά pengar danh từ money
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12-06-2007, 02:17 PM
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#9 (permalink)
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SBR MVP
Join Date: 09-11-07
Posts: 2,501
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I believe the answer to question one is 65,536 combinations. Each game offers you 2 choices and there are 16 games. So the answer is 2 to the 16th power or 65,536.
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12-06-2007, 02:19 PM
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#10 (permalink)
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SBR Hall of Famer
Join Date: 04-05-07
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Quote:
Originally Posted by HedgeHog
I believe the answer to question one is 65,536 combinations. Each game offers you 2 choices and there are 16 games. So the answer is 2 to the 16th power or 65,536.
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i can gurantee you that the parlay odds for 16 games is less than +6,553,600
__________________
"But you can't have your dream without laying something on the line. The key is not to risk what you can't afford to lose. You might think you're different, but someday you gonna want more too. The quesiton is what are you willing to lay on the line."
钱 錢 argent Geld soldi お金 돈 dinheiro деньги dinero เงิน כסף, ממון raha λεφτά pengar danh từ money
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12-06-2007, 02:30 PM
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#11 (permalink)
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SBR Hall of Famer
Join Date: 07-25-07
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?????/
Last edited by pokernut9999 : 12-06-2007 at 02:34 PM.
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12-06-2007, 02:57 PM
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#12 (permalink)
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SBR MVP
Join Date: 09-11-07
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To answer question #2, I need to correct your given info. There are actually 56 regular balls, of which 5 are chosen, and 46 mega balls (sounds dirty) of which one is chosen.
The formula is [56!/ (5! x 51!) ] x 46 = 175,711,536 possibilities.
P.S. 5! = 5x4x3x2x1
I confirmed the answer at the MM site. Do the math for yourself...it works.
Last edited by HedgeHog : 12-06-2007 at 03:01 PM.
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12-06-2007, 03:02 PM
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#13 (permalink)
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SBR Hall of Famer
Join Date: 07-25-07
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Quote:
Originally Posted by HedgeHog
To answer question #2, I need to correct your given info. There are actually 56 regular balls, of which 5 are chosen, and 46 mega balls (sounds dirty) of which one is chosen.
The formula is [56!/ (5! x 51!) ] x 46 = 175,711,536 possibilities.
P.S. 5! = 5x4x3x2x1
I confirmed the answer at the MM site. Do the math for yourself...it works.
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wow , same answer i posted an hour ago.
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12-06-2007, 03:05 PM
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#14 (permalink)
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SBR MVP
Join Date: 09-11-07
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Quote:
Originally Posted by pokernut9999
wow , same answer i posted an hour ago.
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I know. I just wanted to show the math behind your answer. Then I went to the Mega Millions site to confirm your devine genius 
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12-06-2007, 03:06 PM
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#15 (permalink)
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SBR Hall of Famer
Join Date: 07-25-07
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Quote:
Originally Posted by HedgeHog
I know. I just wanted to show the math behind your answer. Then I went to the Mega Millions to confirm your devine genius 
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