A number of people have recently been asking me about how to calculate the fair price of buying or selling a half point when moving off an integer spread (the above post only illustrates how to perform the calculation when moving on to an integer spread.) So I thought I'd just fill in the two remaining buy and sell scenarios.
Let's assume you're moving off of an integer line that occurs with probability p, and further assume that you're buying a half point, and that the theoretical hold on the unadorned line is given by H.
If the relative probability of the buy team winning the bet before the half point was purchased is given by b then the absolute win probability* would be b x (1-p), and the win probability post-purchase would be b x (1-p) + p, the push prob would be 0, and the loss prob would be 1 - b x (1-p) + p. This means that the fair decimal odds, figuring in a theoretical hold of H, would just be:
(1 - H)
--------------- (buying a half point off an integer)
b x (1-p) + p
Similarly, in the case of selling a half point off of an integer, the win probability post-purchase would be b x (1-p) with a push prob of zero. This means that the fair decimal odds, figuring in a theoretical hold of H, would just be:
(1 - H)
--------------- (selling a half point off an integer)
b x (1-p)
(Note that if we were going to express these two formulas in terms of pre-purchase absolute win probability, b', then the two formulas above would simplify to (1-H) / (b'+p) for buying and (1-H) / b' for selling.)
So now we can answer the question from above:

Originally Posted by
Ganchrow
Assuming no change in theoretical hold, and taking the push probabilities above as given, what money line should be associated with a side of Fave -6½ given a market of:
NCAA FB Fave -7 -102
NCAA FB Dog +7 -108
This is a case of buying a half point off an integer. Based on a market of -7 -102/+7 -108, then as in the previous post above the relative win prob of the favorite, b, would be 49.30% with a theoretical hold, H, of 2.36%. From the chart above we see that the spread 7 has an associated push probability, p, of 5.45%.
Hence, the fair decimal odds after buying a half point from -7 to -6½ would be (1-2.36%) / [49.30% x (1-5.45%) + 5.45%] ≈ 1.8754, or US-style odds of -114.23.
*The relative probability of a bet winning refers to the percentage of non-push outcomes where the bet wins. The absolute probability of a bet winning refers to the percentage of all outcomes (including pushes) where the bet wins. (Hence, it should be apparent that in the case of a non-integer spread (where there's no probability of a push) the relative and absolute win probabilities will be equivalent.) This means that for any relative win prob b, and any push prob, p, the absolute win prob is given by b x (1-p).
To give an example:Team A line +100
Team B line +100
Push Probability 20%
The relative win probability of both Teams A and B would then be 50% and the absolute win probability would be 50% (1-20%) = 40%. In other words, the probability of A winning, conditioned on A & B not pushing, is 50%, while the unconditional probability of A winning is 40%.