First of all, thanks for all yours reply!
I will analyze step by step and see how it will go!
For ex: parlay 3 of risking 337 to win 2248
Cincin -2.5
Mi.ST -4.5
Boston -4
If S.F won = 648 - 337 = 311
IF Cin Won = -100
then 2nd game = 630/600 vs Mi.ST , if won 600 - (100 + 337) = 163 (Suck)
If Mi.St won = - 730 (total of losing on both games = -100 - 630)
then 3r game = 1050/1000 vs B.C, if won 1000 - 730 = 270
If B.C won (or 3 games of 2nd parlay) = 2248 - ( 100 + 630 + 1050 ) = 468 .
Well, after trying to analyze like those above steps. I conclude that I should have a straight wager of 200 on Cincin. In that case, if S.F won, I will get 648 - 200 = 448. On the other hand, if Cincin won, I still have another 100 bucks for next parlay teams I will pick later.
